document.write( "Question 638955: 3X+4Y+12= 0 Y ???? ?? ?????? ????? ??? \n" ); document.write( "
Algebra.Com's Answer #402494 by josh_jordan(263)![]() ![]() You can put this solution on YOUR website! To solve for Y, we have to get Y by itself on one side of our equal sign. So, for 3x + 4y + 12 = 0, first we can subtract 12 from both sides of our equal sign: \n" ); document.write( "3x + 4y + 12 - 12 = 0 - 12, giving us\r \n" ); document.write( "\n" ); document.write( "3x + 4y = -12\r \n" ); document.write( "\n" ); document.write( "Next, we can subtract 3x from both sides of our equal sign: 3x - 3x + 4y = -12 - 3x, giving us\r \n" ); document.write( "\n" ); document.write( "4y = -12 - 3x\r \n" ); document.write( "\n" ); document.write( "Finally, we can get the y by itself by dividing both sides by 4:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This leaves us with\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The right side of our equal sign can be simplified, because we know that\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reducing this down results in our final answer\r \n" ); document.write( "\n" ); document.write( "Final Answer: |