document.write( "Question 638904: how do i solve with substitution?\r
\n" ); document.write( "\n" ); document.write( "2x+3y=7
\n" ); document.write( "4x+3y=13
\n" ); document.write( "

Algebra.Com's Answer #402457 by reviewermath(1029)\"\" \"About 
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2x + 3y = 7 ---> 3y = 7 - 2x
\n" ); document.write( "4x + 3y = 13 ---> 4x + (7 - 2x) = 13
\n" ); document.write( "2x + 7 = 13
\n" ); document.write( "x = 3
\n" ); document.write( "3y = 7 - 2(3)
\n" ); document.write( "y = 1/3
\n" ); document.write( "Answer: x = 3 and y = 1/3
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