document.write( "Question 638847: I dont generally have a problem with fractional terms in a quadratic but the following problem has a variable in the fraction and has me confused. Here is the problem:\r
\n" ); document.write( "\n" ); document.write( "bx^2 + 2x + 1/b = 0 (b does not equal 0) solve for x.
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Algebra.Com's Answer #402440 by MathTherapy(10551)\"\" \"About 
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\n" ); document.write( "I dont generally have a problem with fractional terms in a quadratic but the following problem has a variable in the fraction and has me confused. Here is the problem:\r
\n" ); document.write( "\n" ); document.write( "bx^2 + 2x + 1/b = 0 (b does not equal 0) solve for x.\r
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\n" ); document.write( "\n" ); document.write( "\"bx%5E2+%2B+2x+%2B+1%2Fb+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E2x%5E2+%2B+2bx+%2B+1+=+0\" ----- Multiplying by LCD, b\r
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\n" ); document.write( "\n" ); document.write( "Looking for factors of + 1 (c * a) that sum to + 2 (b). These factors are 1 and 1. The replacement for \"b\" is therefore, 1bx and 1bx. We now have:\r
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\n" ); document.write( "\n" ); document.write( "\"b%5E2x%5E2+%2B+bx+%2B+bx+%2B+1+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28b%5E2x%5E2+%2B+bx%29+%2B+%28bx+%2B+1%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "bx(bx + 1) + 1(bx + 1)\r
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\n" ); document.write( "\n" ); document.write( "(bx + 1)(bx + 1) = 0, or \"%28bx+%2B+1%29%5E2+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "bx + 1 = 0\r
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\n" ); document.write( "\n" ); document.write( "bx = - 1\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28x+=+-+1%2Fb%29\"\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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