document.write( "Question 638868: Solve.\r
\n" ); document.write( "\n" ); document.write( "log(3x+1)=2
\n" ); document.write( "

Algebra.Com's Answer #402432 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Assuming this is log to the base ten,
\n" ); document.write( "\"+10%5E2+=+3x+%2B+1+\"
\n" ); document.write( "\"+3x+=+100+-+1+\"
\n" ); document.write( "\"+3x+=+99+\"
\n" ); document.write( "\"+x+=+33+\"
\n" ); document.write( "
\n" );