document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=638776>Question 638776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of 80% acid must be mixed with 25% acid to produce 396ml of 50% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #402399 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=402399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 80% acid needed<BR>\n" );
document.write( "Now we know that the amount of pure acid that exists before the mixture takes place (0.80x+0.25(396-x))has to equal the amount of pure acid that exists after the mixture takes place (0.50*396).  Sooooo:<BR>\n" );
document.write( "0.80x+0.25(396-x)=0.50*396  simplify<BR>\n" );
document.write( "0.80x+99-0.25x=198 subtract 99 from each side and collect like terms<BR>\n" );
document.write( "0.55x=99<BR>\n" );
document.write( "x=180 ml----amount of 80% acid needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.80*180+0.25*216=198<BR>\n" );
document.write( "144+54=198<BR>\n" );
document.write( "198=198\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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