document.write( "Question 636600: The sum of three numbers is 111. The third number is 3 times the first. The first number is 6 less than the second. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #402344 by Susmitha(21)\"\" \"About 
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let the three no's be a,b,c
\n" ); document.write( "given third no is three times the first no
\n" ); document.write( "so c=3a
\n" ); document.write( "and second no is 6 times less than the first no.
\n" ); document.write( "so b=a-6
\n" ); document.write( "also given that a+b+c=111
\n" ); document.write( "now a+a-6+3a=111
\n" ); document.write( " 5a-6=111
\n" ); document.write( " 5a=111+6
\n" ); document.write( " 5a=117
\n" ); document.write( " a=117/5
\n" ); document.write( " a=23.4
\n" ); document.write( " ----------
\n" ); document.write( " b=a-6
\n" ); document.write( " =23.4-6
\n" ); document.write( " b=17.4
\n" ); document.write( " ------------
\n" ); document.write( " c=3a
\n" ); document.write( " =3x23.4
\n" ); document.write( " c=70.2
\n" ); document.write( "-----------------
\n" ); document.write( "to check the answer a+b+c=111
\n" ); document.write( " 23.4+17.4+70.2=111
\n" ); document.write( " 111=111
\n" ); document.write( " hence the answer.......
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