document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=638668>Question 638668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The third of the three numbers is twice the first, and the second, is three times the first. Find the numbers if their sum is 210. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #402333 by </B><A HREF=/tutors/aboutme.mpl?userid=Susmitha><B>Susmitha(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Susmitha><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Susmitha><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=402333\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let a,b,c are the three no's<BR>\n" );
document.write( "given third no is twice the first<BR>\n" );
document.write( "then c=2a<BR>\n" );
document.write( "and second no is thrice the first<BR>\n" );
document.write( "then b=3a<BR>\n" );
document.write( "also given that <BR>\n" );
document.write( "a+b+c=210<BR>\n" );
document.write( "a+3a+2a=210<BR>\n" );
document.write( "6a=210<BR>\n" );
document.write( "a=35<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "b=3a<BR>\n" );
document.write( "b=3x35<BR>\n" );
document.write( "b=105<BR>\n" );
document.write( "------<BR>\n" );
document.write( "c=2a<BR>\n" );
document.write( "c=2x35<BR>\n" );
document.write( "c=70<BR>\n" );
document.write( "------<BR>\n" );
document.write( "now check if a+b+c=210<BR>\n" );
document.write( "     35+105+70=210<BR>\n" );
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document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );