document.write( "Question 638649: the sum of the present ages of sheila and kristine is 42 years. in 9 years, sheila will be 4 years older than 2 times as old as kristine was 2 years ago. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #402319 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! the sum of the present ages of sheila and kristine is 42 years. in 9 years, sheila will be 4 years older than 2 times as old as kristine was 2 years ago. find their present ages. \n" ); document.write( "** \n" ); document.write( "let x=sheila's present age \n" ); document.write( "42-x=kristine's present age \n" ); document.write( ".. \n" ); document.write( "In 9 years: \n" ); document.write( "x+9=sheila's age \n" ); document.write( ".. \n" ); document.write( "2 years ago: \n" ); document.write( "42-x-2=40-x=kristine's age \n" ); document.write( ".. \n" ); document.write( "x+9=2(40-x)+4 \n" ); document.write( "x+9=80-2x+4 \n" ); document.write( "3x=75 \n" ); document.write( "x=25 \n" ); document.write( "42-x=17 \n" ); document.write( "sheila's present age=25 \n" ); document.write( "kristine's present age=17 \n" ); document.write( "..\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |