document.write( "Question 638649: the sum of the present ages of sheila and kristine is 42 years. in 9 years, sheila will be 4 years older than 2 times as old as kristine was 2 years ago. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #402319 by lwsshak3(11628)\"\" \"About 
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the sum of the present ages of sheila and kristine is 42 years. in 9 years, sheila will be 4 years older than 2 times as old as kristine was 2 years ago. find their present ages.
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\n" ); document.write( "let x=sheila's present age
\n" ); document.write( "42-x=kristine's present age
\n" ); document.write( "..
\n" ); document.write( "In 9 years:
\n" ); document.write( "x+9=sheila's age
\n" ); document.write( "..
\n" ); document.write( "2 years ago:
\n" ); document.write( "42-x-2=40-x=kristine's age
\n" ); document.write( "..
\n" ); document.write( "x+9=2(40-x)+4
\n" ); document.write( "x+9=80-2x+4
\n" ); document.write( "3x=75
\n" ); document.write( "x=25
\n" ); document.write( "42-x=17
\n" ); document.write( "sheila's present age=25
\n" ); document.write( "kristine's present age=17
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