document.write( "Question 638374: A wire of length 16 inches is to be cut into two pieces; then each piece will be bent to form a square. Find the length of the two pieces assuming that the sum of the areas of the two squares is 10 square inches. \n" ); document.write( "
Algebra.Com's Answer #402279 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A wire of length 16 inches is to be cut into two pieces; then each piece will be \n" ); document.write( " bent to form a square. \n" ); document.write( "Find the length of the two pieces assuming that the sum of the areas of the two \n" ); document.write( " squares is 10 square inches. \n" ); document.write( ": \n" ); document.write( "Let the length of the sides of the two square be x & y \n" ); document.write( ": \n" ); document.write( "4x + 4y = 16 \n" ); document.write( "simplify, divide by 4 \n" ); document.write( "x + y = 4 \n" ); document.write( "y = (4-x) \n" ); document.write( "and \n" ); document.write( "x^2 + y^2 = 10 \n" ); document.write( ": \n" ); document.write( "Replace y with (4-x) \n" ); document.write( "x^2 + (4-x)^2 = 10 \n" ); document.write( "FOIL (4-x)(4-x) \n" ); document.write( "x^2 + 16 - 8x + x^2 = 10 \n" ); document.write( "Combine like terms on the left \n" ); document.write( "x^2 + x^2 - 8x + 16 - 10 = 0 \n" ); document.write( "2x^2 - 8x + 6 = 0 \n" ); document.write( "simplify, divide by 2 \n" ); document.write( "x^2 - 4x + 3 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x-1)(x-3) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "x = 1, then y = 3 \n" ); document.write( "and \n" ); document.write( "x = 3, then y = 1 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can check if this is true in the two original equations \n" ); document.write( " |