document.write( "Question 638374: A wire of length 16 inches is to be cut into two pieces; then each piece will be bent to form a square. Find the length of the two pieces assuming that the sum of the areas of the two squares is 10 square inches. \n" ); document.write( "
Algebra.Com's Answer #402279 by ankor@dixie-net.com(22740)\"\" \"About 
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A wire of length 16 inches is to be cut into two pieces; then each piece will be
\n" ); document.write( " bent to form a square.
\n" ); document.write( "Find the length of the two pieces assuming that the sum of the areas of the two
\n" ); document.write( " squares is 10 square inches.
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\n" ); document.write( "Let the length of the sides of the two square be x & y
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\n" ); document.write( "4x + 4y = 16
\n" ); document.write( "simplify, divide by 4
\n" ); document.write( "x + y = 4
\n" ); document.write( "y = (4-x)
\n" ); document.write( "and
\n" ); document.write( "x^2 + y^2 = 10
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\n" ); document.write( "Replace y with (4-x)
\n" ); document.write( "x^2 + (4-x)^2 = 10
\n" ); document.write( "FOIL (4-x)(4-x)
\n" ); document.write( "x^2 + 16 - 8x + x^2 = 10
\n" ); document.write( "Combine like terms on the left
\n" ); document.write( "x^2 + x^2 - 8x + 16 - 10 = 0
\n" ); document.write( "2x^2 - 8x + 6 = 0
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "x^2 - 4x + 3 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-1)(x-3) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "x = 1, then y = 3
\n" ); document.write( "and
\n" ); document.write( "x = 3, then y = 1
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\n" ); document.write( "You can check if this is true in the two original equations
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