document.write( "Question 638031: The distance between city A and B is 28 km. Two hikers left from each city (One from city A to city B and the other from city B to city A) heading towards each other at the same speed. The hiker from city A rested for an hour after having walked 9 km and then continued at a speed greater than 1 km/hour than his previous speed, then rested again 4 km away from city B. There he met the hiker from city B, who walked at a constant speed without resting until the two met. What were the speeds of the two hikers? \n" ); document.write( "
Algebra.Com's Answer #402276 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The distance between city A and B is 28 km. \n" ); document.write( "Two hikers left from each city (One from city A to city B and the other from \n" ); document.write( " city B to city A) heading towards each other at the same speed. \n" ); document.write( "The hiker from city A rested for an hour after having walked 9 km and then \n" ); document.write( " continued at a speed greater than 1 km/hour than his previous speed, then \n" ); document.write( " rested again 4 km away from city B. \n" ); document.write( "There he met the hiker from city B, who walked at a constant speed without \n" ); document.write( " resting until the two met. \n" ); document.write( " What were the speeds of the two hikers? \n" ); document.write( ": \n" ); document.write( "Let s = speed of the two hikers \n" ); document.write( "then \n" ); document.write( "(s+1) = speed of the A after his 1 hr rest \n" ); document.write( ": \n" ); document.write( "Find the distance hiker A traveled after his rest, to meet B, 4 km from City B \n" ); document.write( "28-9-4 = 15 km \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply both sides by s \n" ); document.write( " \n" ); document.write( "24s + 9 = (s+1)(4-s) \n" ); document.write( "FOIL the right side \n" ); document.write( "24s + 9 = 4s - s^2 + 4 - s \n" ); document.write( "24s + 9 = 3s - s^2 + 4 \n" ); document.write( "Combine on the left \n" ); document.write( "s^2 + 24s - 3s + 9 - 4 = 0 \n" ); document.write( "s^2 + 21s + 5 = 0 \n" ); document.write( "Actually this equation has two negative solutions so the given scenario is not possible. \n" ); document.write( "It seems unreasonable, to find a speed, where A travels 24 km (+ a rest), \n" ); document.write( "while B travels 4 km \n" ); document.write( " \n" ); document.write( " |