document.write( "Question 637987: solve for x: log(2x-1) = 1 \n" ); document.write( "
Algebra.Com's Answer #402152 by ankor@dixie-net.com(22740)\"\" \"About 
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solve for x: log(2x-1) = 1
\n" ); document.write( "Write the exponent equiv of logs
\n" ); document.write( "(2x-1) = 10^1
\n" ); document.write( "2x - 1 = 10
\n" ); document.write( "2x = 10 + 1
\n" ); document.write( "2x = 11
\n" ); document.write( "x = 11/2
\n" ); document.write( "x = 5.5
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this on your calc, enter: log(2(5.5)-1) \n" ); document.write( "
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