document.write( "Question 58659: Someone Help Please\r
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Algebra.Com's Answer #40209 by Edwin McCravy(20060) $\"\"$ $\"About$

You can put this solution on YOUR website!

Someone Help Please\r\n" );
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document.write( "solve |3x+5| - 7 >  -5 answer in interval notation\r\n" );
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document.write( "First isolate the absolute value on the left by ading\r\n" );
document.write( "7 to both sides\r\n" );
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document.write( "      |3x+5| - 7 > -5\r\n" );
document.write( "              +7   +7\r\n" );
document.write( "     ----------------- \r\n" );
document.write( "          |3x+5| > 2\r\n" );
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document.write( "There are two rules for removing absolute value bars\r\n" );
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document.write( "1. To remove the absolute value bars of\r\n" );
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document.write( "     |expression| < A , where A is a positive number,\r\n" );
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document.write( "replace it by this:\r\n" );
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document.write( "     -A < expression < +A\r\n" );
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document.write( "2. To remove the absolute value bars of\r\n" );
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document.write( "     |expression| > A , where A is a positive number,\r\n" );
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document.write( "replace it by this:\r\n" );
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document.write( "   expression < -A  OR expression > A\r\n" );
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document.write( "Since |3x+5| > 2 involves >, we replace it by:\r\n" );
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document.write( "     3x + 5 < -2   OR   3x + 5 >  2\r\n" );
document.write( "         -5   -5            -5   -5\r\n" );
document.write( "    ------------       -------------\r\n" );
document.write( "     3x     < -7   OR   3x     > -3    \r\n" );
document.write( "               \r\n" );
document.write( "         x < -7/3  OR  x > -1\r\n" );
document.write( "                \r\n" );
document.write( "     <=========o-----------o==========>\r\n" );
document.write( "             -7/3        -1\r\n" );
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document.write( "         (-¥, -7/3) È (-1, ¥)\r\n" );
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document.write( "Edwin

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