document.write( "Question 638062: Can you please help me evaluate 5^log1/5(1/2)\r
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document.write( "Thank in advance
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document.write( "Vijji \n" );
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Algebra.Com's Answer #402026 by Theo(13342) You can put this solution on YOUR website! it's hard to determine what your problem is. \n" ); document.write( "this is what i think it is. \n" ); document.write( "5^(log(1/5,(1/2) \n" ); document.write( "what this means is 5 raised to the power of (the log of 1/2 to the base of 1/5). \n" ); document.write( "if that's what you meant, then the solution would be as follows. \n" ); document.write( "let 1/2 = .5 \n" ); document.write( "let 1/5 = .2 \n" ); document.write( "problem then becomes: \n" ); document.write( "5^(log of .5 to the base of .2) \n" ); document.write( "first think we want to do is convert the log from the base of .2 to the base of 10. \n" ); document.write( "this allows you to use the LOG function of your calculator. \n" ); document.write( "the conversion formula would be: \n" ); document.write( "log of .5 to the base of .2 equals the log of .5 to the base of 10 divided by the log of .2 to the base of 10. \n" ); document.write( "the log of .5 to the base of 10 divided by the log of .2 to the base of 10 would look like: \n" ); document.write( "LOG(.5)/LOG(.2) \n" ); document.write( "replacing that in your expression make your expression equal to: \n" ); document.write( "5^(LOG(.5)/LOG(.2)) \n" ); document.write( "use your calculator to solve for LOG(.5)/LOG(.2) and your expression becomes: \n" ); document.write( "5^(.4306765581) \n" ); document.write( "use your calculator again to get: \n" ); document.write( "5^(.4306765581) = 2. \n" ); document.write( "that's your answer assuming i interpreted your problem correctly.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |