document.write( "Question 58498: Here's a word problem that has me stumped, a small firm produces both AM and AM/FM car radios. The AM radios take 15 h to produce, and the AM/FM radios take 20 h. The number of production hours is limited to 300 h per week. The plant’s capacity is limited to a total of 18 radios per week and existing orders require that at least 4 AM radios and at least 3 AM/FM radios are produced per week. Write a system of inequalities representing this situation. Then, draw a graph of the feasible region given these conditions, in which x is the number of AM radios and y the number of AM/FM radios. How do you solve this?
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Algebra.Com's Answer #40201 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Here's a word problem that has me stumped, a small firm produces both AM and AM/FM car radios. The AM radios take 15 h to produce, and the AM/FM radios take 20 h. The number of production hours is limited to 300 h per week. The plant’s capacity is limited to a total of 18 radios per week and existing orders require that at least 4 AM radios and at least 3 AM/FM radios are produced per week. Write a system of inequalities representing this situation. Then, draw a graph of the feasible region given these conditions, in which x is the number of AM radios and y the number of AM/FM radios. How do you solve this? \n" ); document.write( ": \n" ); document.write( "Let x = no. of AM radios; Let y = no.of AM/FM radios \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "\"The AM radios take 15 h to produce, and the AM/FM radios take 20 h. The number of production hours is limited to 300 h per week.\" \n" ); document.write( "The hour equation: \n" ); document.write( "15x + 20y =< 300 \n" ); document.write( "Arrange it \"y=\" in order graph it \n" ); document.write( "20y =< 300 - 15x \n" ); document.write( "y =< 300/20 - (15/20)x \n" ); document.write( "y =< 15 - .75x; plotted as the red line \n" ); document.write( ": \n" ); document.write( "\"The plant’s capacity is limited to a total of 18 radios\" \n" ); document.write( "The quantity equation: \n" ); document.write( "x + y <= 18 \n" ); document.write( "y <= 18 - x; plotted as the green line \n" ); document.write( ": \n" ); document.write( "\"At least 4 AM Radios\" \n" ); document.write( "x => 4 \n" ); document.write( "This will be vertical line parallel to y axis, passing thru x =>4. You will have \n" ); document.write( "to draw this in yourself \n" ); document.write( ": \n" ); document.write( "\"At least 3 AM/FM Radios\" \n" ); document.write( "y => 3, plotted as the black line \n" ); document.write( ": \n" ); document.write( "The graph: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Note that the feasibility region would be bounded by: \n" ); document.write( "1. area equal or above the horizontal line going thru y = 3, \n" ); document.write( "2. the vertical line that you will draw going thru x = 4, or to the right, \n" ); document.write( "3. Equal or below the red and the green lines whichever is lowest. \n" ); document.write( ": \n" ); document.write( "Did this make sense to you?? \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |