document.write( "Question 638057: graph y= 4 log base 2 (x+4)+2 \n" ); document.write( "
Algebra.Com's Answer #402009 by lwsshak3(11628) ![]() You can put this solution on YOUR website! graph y= 4 log base 2 (x+4)+2 \n" ); document.write( "I don't have the means or know how to graph it for you but I can show you one way to do it. \n" ); document.write( "All log curves regardless of base have the y-axis as an asymptote and cross the x-axis at 1. logb(1)=0 \n" ); document.write( "The basic logx curve starts from (0,-∞), crosses the x-axis at 1 and gradually increases to ∞. \n" ); document.write( "For given equation:y= 4 log base 2 (x+4)+2 \n" ); document.write( "(x+4) moves the asymptote 4 units left, that is, you have an asymptote at y=-4 and x-intercept at -3. \n" ); document.write( "The multiplier 4 stretches the curve making it more positive for x>1 and more negative for x<1. No change to position of asymptote or x-intercept. Finally, the +2 in the equation bumps the entire curve 2 units up. The x-intercept point is moved to (-3,2), no change to position of asymptote. \n" ); document.write( ".. \n" ); document.write( "note: If you have a graphing calculator it would greatly help you follow steps I have described. \n" ); document.write( " |