document.write( "Question 638026: mixture a is 30 percent suger, 15 percent ciiamon, and the rest flour. Mixture b is 3/4 sugar and 1/4 flour. If we comine 2 cups of mixture a with 5 cups of mixture b and 1 cup of flour, what percent of the resluting mixture will be flour?
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Algebra.Com's Answer #402005 by lwsshak3(11628)\"\" \"About 
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mixture a is 30 percent suger, 15 percent ciiamon, and the rest flour. Mixture b is 3/4 sugar and 1/4 flour. If we comine 2 cups of mixture a with 5 cups of mixture b and 1 cup of flour, what percent of the resulting mixture will be flour?
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\n" ); document.write( "let x=% flour in resulting mixture
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\n" ); document.write( "mixture a: 2 cups
\n" ); document.write( "sugar=30%*2=0.6 cup
\n" ); document.write( "cinnamon=15%*2=0.3 cup
\n" ); document.write( "flour=55%*2=1.1 cup
\n" ); document.write( "..
\n" ); document.write( "mixture b: 5 cups
\n" ); document.write( "sugar=3/4*5=15/4 cup
\n" ); document.write( "flour=1/4*5=5/4=1.25 cup
\n" ); document.write( "..
\n" ); document.write( "Resulting mixture: 8 cups
\n" ); document.write( "flour,x=1.1+1.25+1=3.35 cups
\n" ); document.write( "x=3.35/8≈.419
\n" ); document.write( "% flour in resulting mixture≈41.9% \n" ); document.write( "
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