document.write( "Question 637975: The width of a rectangle is two less than its length. If the area of the rectangle is 42, what is the length of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #401985 by josh_jordan(263)\"\" \"About 
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In order to solve this problem, first find the given. In this case, it tells you that the width is 2 less than the length. In other words, W=L-2. Since the question involves the area of a rectangle, we will need to use the formula for finding the area of a rectangle, which is A=L X W, where L is length and W is width. So, let's set up our two equations:\r
\n" ); document.write( "\n" ); document.write( "W=L - 2
\n" ); document.write( "42=L X W\r
\n" ); document.write( "\n" ); document.write( "We can substitute L - 2 for the W in the second equation. So, we would have\r
\n" ); document.write( "\n" ); document.write( "42 = L X (L-2) or L(L-2)\r
\n" ); document.write( "\n" ); document.write( "We would multiply the L-2 by L, which is L^2-2L, so we now have\r
\n" ); document.write( "\n" ); document.write( "42 = L^2 - 2L\r
\n" ); document.write( "\n" ); document.write( "When we subtract 42 from both sides of our equation, we see that we are left with a linear equation:\r
\n" ); document.write( "\n" ); document.write( "L^2 - 2L - 42 = 0\r
\n" ); document.write( "\n" ); document.write( "So, to solve for L (the length), use the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-%28-2%29%2B-sqrt%28%28-2%29%5E2-4%2B1%2A-42%29%29%2F%282%2A1%29\"\r
\n" ); document.write( "\n" ); document.write( "which is\r
\n" ); document.write( "\n" ); document.write( "\"x=%282%2B-sqrt%284%2B168%29%29%2F%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%282%2B-sqrt%28172%29%29%2F%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%282%2B-sqrt%284%2A43%29%29%2F%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%282%2B-2sqrt%2843%29%29%2F%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%281%2B-sqrt%2843%29%29\"\r
\n" ); document.write( "\n" ); document.write( "So, the length of our rectangle is \"1%2B-sqrt%2843%29\"\r
\n" ); document.write( "\n" ); document.write( "We know that the width of our rectangle 2 less than our length, so the width would be \"1%2B-sqrt%2843%29-2\", which is \"-1%2B-sqrt%2843%29\"\r
\n" ); document.write( "\n" ); document.write( "Length = \"1%2B-sqrt%2843%29\"
\n" ); document.write( "Width = \"-1%2B-sqrt%2843%29\"\r
\n" ); document.write( "\n" ); document.write( "However, neither the length nor the width of a rectangle can be a negative number. So, our length cannot be \"1-sqrt%2843%29\", because that is a negative number. Similarly, our width cannot be \"-1-sqrt%2843%29\", because that too is a negative number. So, our final answer would be:\r
\n" ); document.write( "\n" ); document.write( "Length = \"1%2Bsqrt%2843%29\"
\n" ); document.write( "Width = \"-1%2Bsqrt%2843%29\"\r
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