document.write( "Question 637995: Graph the liner equation\r
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Algebra.Com's Answer #401955 by reviewermath(1029)\"\" \"About 
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"1+x+%2B+-1+y+=+3\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-1%2F-1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 3/1 = 3.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 3/-1 = -3.
  • Slope is -1/-1 = 1.
  • Equation in slope-intercept form: y=1*x+-3.
\"graph%28+500%2C+500%2C+3-8%2C+3%2B8%2C+-3-8%2C+-3%2B8%2C+1%2Ax%2B-3+%29+\"\n" ); document.write( "
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