document.write( "Question 637911: (a)if log x , log(x+2) , log(x+16) are three consecutive terms of an AP, find the value of x.
\n" ); document.write( "(B)the sixth terms of an AP is Twice the Second term and the fifth term exceeds the first term by 10.find first term and the common difference. \n" ); document.write( "

Algebra.Com's Answer #401939 by reviewermath(1029) $\"\"$ $\"About$

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(a) log(x+2) - log x = log(x + 16) - log (x + 2)
\n" ); document.write( " log [(x + 2)/x] = log [(x + 16)/(x + 2)]
\n" ); document.write( " $\"+%28x+%2B+2%29%2Fx+=+%28x+%2B+16%29%2F%28x+%2B+2%29+\"$ , cross multiply
\n" ); document.write( " $\"+%28x+%2B+2%29%5E2+=+x%28x+%2B+16%29+\"$
\n" ); document.write( " $\"+x%5E2+%2B+4x+%2B+4+=+x%5E2+%2B+16x\"$
\n" ); document.write( " $\"+12x+=+4\"$
\n" ); document.write( " Answer: $\"highlight%28x+=+1%2F3%29\"$ \r
\n" ); document.write( "\n" ); document.write( "(b) Let x be the first term and k be the common difference.
\n" ); document.write( " 6th term = x + 5k
\n" ); document.write( " 2nd term = x + k
\n" ); document.write( " 5th term = x + 4k\r
\n" ); document.write( "\n" ); document.write( " Equations:
\n" ); document.write( " (x + 5k) = 2(x + k) or x - 3k = 0
\n" ); document.write( " (x + 4k) - x = 10 or 4k = 10, therefore k = 2.5
\n" ); document.write( " So x - 3(2.5) = 0, therefore x = 7.5
\n" ); document.write( "
\n" ); document.write( "Answer: The first term is 7.5 and the common difference is 2.5. \n" ); document.write( "

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