document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636471>Question 636471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I need help with several questions.\r<BR>\n" );
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document.write( "Solve for x.<BR>\n" );
document.write( "6^(log_6 of x^2) = x+30 I'm not sure if this makes sense, but that log_6 of x^2 literally shows up as an exponent on my worksheet.\r<BR>\n" );
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document.write( "2-log_(2-x)of 2x = 0\r<BR>\n" );
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document.write( "I'm not sure if this makes sense either...\r<BR>\n" );
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document.write( "Let ln A=8, ln B=-3, and ln C=5. Evaluate each of the following.<BR>\n" );
document.write( "1. ln 4 sqrt of A. The 4 is part of the square root.<BR>\n" );
document.write( "2. ln (Be)/C<BR>\n" );
document.write( "3. ln sqrt of ((A^5Ce^2)/B^3) meaning everything is under the square root.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401935 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401935\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x.<BR>\n" );
document.write( "6^(log_6 of x^2) = x+30<BR>\n" );
document.write( "Base raised to log of number=number (left side)<BR>\n" );
document.write( "x^2=x+30<BR>\n" );
document.write( "x^2-x-30=0<BR>\n" );
document.write( "(x-6)(x+5)=0<BR>\n" );
document.write( "x=-5 (reject, x>0)<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2-log_(2-x)of 2x = 0<BR>\n" );
document.write( "log_(2-x)of 2x =2<BR>\n" );
document.write( "convert to exponential form (base(2-x) raised to log of number(2)=number(2x)<BR>\n" );
document.write( "(2-x)^2=2x<BR>\n" );
document.write( "4-4x+x^2=2x<BR>\n" );
document.write( "x^2-6x+4=0<BR>\n" );
document.write( "solve by quadratic formula<BR>\n" );
document.write( "x&#8776;5.236.. (reject,(2-x)>0)<BR>\n" );
document.write( "or<BR>\n" );
document.write( "x&#8776;.764..<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Let ln A=8, ln B=-3, and ln C=5. Evaluate each of the following.<BR>\n" );
document.write( "1. ln 4 sqrt of A. The 4 is part of the square root.<BR>\n" );
document.write( "ln&#8730;4A<BR>\n" );
document.write( "=ln(2*&#8730;A)<BR>\n" );
document.write( "=ln2+(1/2)lnA<BR>\n" );
document.write( "=ln2+(1/2)*8<BR>\n" );
document.write( "=ln2+4<BR>\n" );
document.write( "=.693+4<BR>\n" );
document.write( "=4.693<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2. ln (Be)/C<BR>\n" );
document.write( "=lnB+lne-lnC<BR>\n" );
document.write( "=-3+1-5<BR>\n" );
document.write( "=-7<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3. ln sqrt of ((A^5Ce^2)/B^3)<BR>\n" );
document.write( "=(1/2)[5lnA+lnC+2lne-3lnB]<BR>\n" );
document.write( "=(1/2)[5*8+5+2-3*-3]<BR>\n" );
document.write( "=(1/2)[40+7+9]<BR>\n" );
document.write( "=[56]/2<BR>\n" );
document.write( "=28 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );