document.write( "Question 637872: I don't know how to do this math problem. I need help fast because I have a high school Regents exam tomorrow morning and I don't know if a question similar to this one could be on the exam. The problem is: \"The sum of three consecutive odd integers is 18 less than five times the middle number. Find the three integers. [Only alebraic solution can receive full credit.]\" PLEASE HELP! \n" ); document.write( "
Algebra.Com's Answer #401930 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
My granddaughter may be taking the same regents, so I'm rushing the solution to you.
\n" ); document.write( "Let n = the first odd integer
\n" ); document.write( "Then the next higher odd integer is n+2 (n+1 is an even number)
\n" ); document.write( "And the third and largest odd integer is n+4 (or n+2+2)
\n" ); document.write( "The sum of them = 5*(middle odd integer) less 18
\n" ); document.write( "n + (n+2) + (n+4) = 5*(n+2) - 18
\n" ); document.write( "Simplify by adding like terms
\n" ); document.write( "3n + 6 = 5n + 10 -18
\n" ); document.write( "6 - 10 + 18 = 5n - 3n
\n" ); document.write( "2n = 14
\n" ); document.write( "n = 7 OK?
\n" ); document.write( "Answer: the three consecutive odd integers are 7, 9, 11
\n" ); document.write( "Let's check.
\n" ); document.write( "Does (7+9+11 = 5(9)-18)?
\n" ); document.write( "Does (27 = 45-18)?
\n" ); document.write( "Does (27=27)? Yes \n" ); document.write( "
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