document.write( "Question 637688: x & y travel 4000m n finish race in tie.first x travel 50% than Y and Y travels 50% faster than x n end in tie.before y travelled 50% faster then X what distance had it covered? \n" ); document.write( "
Algebra.Com's Answer #401928 by ankor@dixie-net.com(22740)\"\" \"About 
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Attempt to rewrite this so it makes sense.
\n" ); document.write( ":
\n" ); document.write( "x & y travel 4000m and finish the race in a tie.
\n" ); document.write( "At first x travels 50% faster than Y and then,
\n" ); document.write( "Y travels 50% faster than x, and the race ends in a tie.
\n" ); document.write( "Before y traveled 50% faster then X, what distance had he covered?
\n" ); document.write( ":
\n" ); document.write( "let s = the original speed of y
\n" ); document.write( "and
\n" ); document.write( "1.5s = the original speed of x
\n" ); document.write( "then
\n" ); document.write( "1.5(1.5s)= 2.25s = final speed of y
\n" ); document.write( ":
\n" ); document.write( "Let d = distance y traveled at speed s
\n" ); document.write( "then
\n" ); document.write( "(4000-d) = speed y traveled at speed 2.25s
\n" ); document.write( ":
\n" ); document.write( "Write a time equation:
\n" ); document.write( "y's total travel time = x's travel time
\n" ); document.write( "\"d%2Fs\" + \"%28%284000-d%29%29%2F%282.25s%29\" = \"4000%2F%281.5s%29\"
\n" ); document.write( "Multiply by least common multiple: 27s
\n" ); document.write( "27s*\"d%2Fs\" + 27s*\"%28%284000-d%29%29%2F%282.25s%29\" = 27s*\"4000%2F%281.5s%29\"
\n" ); document.write( "Cancel out the denominators, results:
\n" ); document.write( "27d + 12(4000-d) = 18(4000)
\n" ); document.write( "27d + 48000 - 12d = 72000
\n" ); document.write( "27d - 12d = 72000 - 48000
\n" ); document.write( "15d = 24000
\n" ); document.write( "d = \"24000%2F15\"
\n" ); document.write( "d = 1600 meters traveled before y changed his speed to 1.5 times x's speed \n" ); document.write( "
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