document.write( "Question 58618: Find the slope of the line:
\n" ); document.write( "a. 3x-6y=7
\n" ); document.write( "b. y + 5 = 2
\n" ); document.write( "c. 2x= 5
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Algebra.Com's Answer #40185 by funmath(2933)\"\" \"About 
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Find the slope of the line:
\n" ); document.write( "a. 3x-6y=7
\n" ); document.write( "Put the equation in slope intercept form: \"highlight%28y=mx%2Bb%29\", m=slope and (0,b)=y-intercept.
\n" ); document.write( "-3x+3x-6y=-3x+7
\n" ); document.write( "-6y=-3x+7
\n" ); document.write( "\"-6y%2F-6=%28-3%2F-6%29x%2B7%2F-6\"
\n" ); document.write( "\"y=%281%2F2%29x-7%2F6\"
\n" ); document.write( "\"y=highlight%281%2F2%29x-7%2F6\" the slope, m=1/2
\n" ); document.write( ":
\n" ); document.write( "b. y + 5 = 2
\n" ); document.write( "y+5-5=2-5
\n" ); document.write( "y=-3
\n" ); document.write( "This is a special case, whenever you have y=k and k= any real number and there's no x. You have a horizontal line going through y=k, in this case a horizontal line going through y=-3. Horizontal lines don't go up and down so their slopes are m=0.
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\n" ); document.write( "c. 2x= 5
\n" ); document.write( "2x/2=5/2
\n" ); document.write( "x=5/2
\n" ); document.write( "This is another special case (don't worry, there's only two), whenever you have x=k and k is any real number and there's no y. You have a vertical line going through x=k, in this case a vertical line going through x=5/2. Vertical lines go forever up and forever down at the same time so their slopes are undefined.
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\n" ); document.write( "Happy Calculating!!!
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