document.write( "Question 637713: What is the best way to solve this equation in step by step ?\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%282%2Fx%29+-+sqrt+%28x%2F2%29+=+1%2Fsqrt+%282%29+\"\r
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Algebra.Com's Answer #401825 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( " What is the best way to solve this equation in step by step ?\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%282%2Fx%29+-+sqrt+%28x%2F2%29+=+1%2Fsqrt+%282%29+\"\r
\n" ); document.write( "\n" ); document.write( "I'm profoundly grateful for help.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%282%2Fx%29+-+sqrt+%28x%2F2%29+=+1%2Fsqrt+%282%29+\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%282%29%2Fsqrt%28x%29+-+sqrt%28x%29%2Fsqrt%282%29+=+1%2Fsqrt+%282%29+\" ---- Separate the radicals \r
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\n" ); document.write( "\n" ); document.write( "\"%28sqrt%282%29%2Asqrt%282%29%29+-+%28sqrt%28x%29%2Asqrt%28x%29%29+=+sqrt%28x%29\" ----- Multiplying equation by LCD, \"sqrt%28x%29%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%282%5E2%29+-+sqrt%28x%5E2%29+=+sqrt%28x%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"2+-+x+=+sqrt%28x%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"%282+-+x%29%5E2+=+%28sqrt%28x%29%29%5E2\" ----- Squaring both sides of equation\r
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\n" ); document.write( "\n" ); document.write( "\"4+-+4x+%2B+x%5E2+=+x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+4x+-+x+%2B+4+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+5x+%2B+4+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "(x - 4)(x - 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "x = 4 or x = 1\r
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\n" ); document.write( "\n" ); document.write( "Substituting 4 for x in original equation results in x = 4 being an EXTRANEOUS solution. On the other hand, substituting 1 for x makes the original equation true, so \"highlight_green%28x=1%29\".\r
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\n" ); document.write( "\n" ); document.write( "You can do the checks by plugging in 4 for x, and then 1 for x in original equation.\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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