document.write( "Question 637537: Help on this stumper would be greatly appreciated -
\n" ); document.write( "Daniel mixes a powdered sports drink with cold water. For best taste, the mix should be 96% water. If Daniel has used 16 scoops of powder and added 2 quarts of water, how many gallons of water should he add, given that each scoop is 1/4 cup?
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Algebra.Com's Answer #401784 by KMST(5328)\"\" \"About 
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I am to assume that the problem meant to say that you have to mix 4 parts of powder to 96 parts of water, measuring by volume.
\n" ); document.write( "That is a 1:24 ratio (\"4%2F96=1%2F24\").
\n" ); document.write( "For the 2 scoops (1/2 cup) of powder Daniel added, he should have used 12 cups (\"24%2A%281%2F2%29=12\")
\n" ); document.write( "There are 4 cups in a quart, so Daniel should have used 3 quarts of water (\"12%2F4=3\").
\n" ); document.write( "Since Daniel only added 2 quarts, he needs to add 1 quart more.
\n" ); document.write( "There are 4 quarts in a gallon, so Daniel needs to add \"highlight%281%2F4%29\" gallon of water.
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\n" ); document.write( "NOTES:
\n" ); document.write( "To a chemist, like me, the problem sounds wrong. With any scientifically sound interpretation of the wording, it would impossible to solve due to lack of information.
\n" ); document.write( "96% water would mean 96 grams of water mixed with 4 grams of powder, making 100 g mixture, and if w/w (weight in weight) were specified, it would be even clearer.
\n" ); document.write( "The density of water can be assumed to be 1.00g/mL, but we do not know the bulk density of the powder, so we do not know how many grams of powder were used.
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\n" ); document.write( "It would be worse if the drink had to be 4% powder w/v (weight in volume, meaning 4 g powder in 100 mL final drink volume), beause we would not know the density of the correctly formulated drink.\r
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