document.write( "Question 637582: solve the equation for y
\n" ); document.write( "y^3/2 -12y^1/2 +32y^-1/2 =0\r
\n" ); document.write( "\n" ); document.write( "HELP!!! TY!
\n" ); document.write( "

Algebra.Com's Answer #401780 by meetkisai(17)\"\" \"About 
You can put this solution on YOUR website!
y^3/2 -12y^1/2 +32y^-1/2 =0
\n" ); document.write( "=> \"+y+%2A+sqrt%28y%29+-+12+%2A+sqrt%28y%29+%2B+32+%2F+sqrt%28y%29+=+0+\"
\n" ); document.write( "=> \"y%5E2+-+12y+%2B+32+=0\"
\n" ); document.write( "=> \"y%5E2+-+8y+-4y+%2B+32+=+0\"
\n" ); document.write( "=> \"%28y-8%29+%28y-4%29+=+0\"
\n" ); document.write( "=> y=(8, 4)
\n" ); document.write( "
\n" );