document.write( "Question 58621: Graph the linear inequalitities:
\n" ); document.write( "a. 3x-y>9
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Algebra.Com's Answer #40178 by megaroo11891(5) $\"\"$ $\"About$

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a. 3x-y>9
\n" ); document.write( "b. 2x-3y< -6\r
\n" ); document.write( "\n" ); document.write( "First off, you need to change these problems into slope intercept form (y=mx+b). To do that for the first problem, subtract 3x from both sides to get -y > -3x + 9. Now, since your Y value can't be negative, you must multiply by -1 on both sides to get y < 3x - 9 (remember that whenever you multiply or divide by a negative, you change the signs). For the second problem, you must subtract 2x from both sides to get -3y < -2x - 6. Now you must divide both sides by -3 to get y > 2/3x + 2 (remember that whenever you multiply or divide by a negative, you change the signs). Your graph would look something similar to this, but the lines would be dashed because it is < or >.\r
\n" ); document.write( "\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y%3C3x-9%2C+y%3E0.667x%2B2%29+\"$ \n" ); document.write( "

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