document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=637461>Question 637461</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this equation \r<BR>\n" );
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document.write( "4-|1-2|  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401690 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The abs(anything) is ALWAYS positive. If the anything is positive the abs(anything) is anything. If anything is negative then abs(anything) is -anything. In your problem anything is (1-2) which is -1. Using my rule<BR>\n" );
document.write( "abs(1-2) = abs(-1) = -(-1) = +1<BR>\n" );
document.write( "Your problem reduces to <BR>\n" );
document.write( "4-Abs(1-2) <BR>\n" );
document.write( "= 4 - [+1] = 4 - 1 = 3<BR>\n" );
document.write( "Your answer is 3<BR>\n" );
document.write( "Your answer is NOT [4 - (-1)] = [4 + 1] = 5 </SPAN>\n" );
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