document.write( "Question 637463: absolute value of (4x + 2) is less than or equal to 14 \n" ); document.write( "

Algebra.Com's Answer #401682 by DrBeeee(684) $\"\"$ $\"About$

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Solve for domain of x that satisfies abs(4x+2) <= 14
\n" ); document.write( "The \"trick\" here is to use the DrBeeee identity for absolute value.
\n" ); document.write( "If y > 0, then abs(y) = y
\n" ); document.write( "If y < 0, then abs(y) = -y
\n" ); document.write( "Apply my identity to your problem;
\n" ); document.write( "If (4x+2)>0 then abs(4x+2) = 4x+2
\n" ); document.write( "solve 4x+2 > 0 gives x > -1/2 and
\n" ); document.write( "4x+2 <= 14 gives x <= 3
\n" ); document.write( "If (4x+2) < 0 then abs(4x+2) = -(4x+2)
\n" ); document.write( "solve 4x+2 < 0 gives x < -1/2 and
\n" ); document.write( "-(4x+2) <= 14 gives x >= -3
\n" ); document.write( "Thus the solution domain for x is
\n" ); document.write( "-3 <= x <= 3 \n" ); document.write( "

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