document.write( "Question 637395: The height of a curved support beam can be modeled by
\n" ); document.write( "f(x) = -x^2/288+18
\n" ); document.write( "Find the height and width of the beam.
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Algebra.Com's Answer #401653 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "f(x)=-x^2/288+18 V(0,18), parabola opening downward, height of beam is \"18\"
\n" ); document.write( "If f(x) = 0 ⇒ x^2 = 18*288 and \"x+=sqrt%285184%29+=++72\"
\n" ); document.write( "width of the beam is \"72+%2B+72+=+144\"
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