document.write( "Question 58603: At 10Am, adam started out at 60 kilometers per hour to catch tom , who had a three hour head start. If adam was still 70 kilometers behind at 6 pm, how fast was tom driving? \n" ); document.write( "
Algebra.Com's Answer #40165 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
At 10Am, adam started out at 60 kilometers per hour to catch tom , who had a three hour head start. If adam was still 70 kilometers behind at 6 pm, how fast was tom driving?
\n" ); document.write( "--------------
\n" ); document.write( "Adam DATA:
\n" ); document.write( "rate= 60 km/hr ; time = 8 hr. ; distance = tr= 480 km
\n" ); document.write( "---------
\n" ); document.write( "Tom DATA:
\n" ); document.write( "time=8+3 = 11 hr;
\n" ); document.write( "Let Tom's rate be x km/hr
\n" ); document.write( "In 3 hrs he goes 3x km
\n" ); document.write( "He then covers the 480 km that Adam covers later
\n" ); document.write( "He then is 70 km ahead of Adam
\n" ); document.write( "Tom's distance = 3x+480+70=3x+550 km
\n" ); document.write( "Tom's distance is also 11x because he was on the road for 11 hours
\n" ); document.write( "EQUATION:
\n" ); document.write( "3x+550=11x
\n" ); document.write( "8x=550
\n" ); document.write( "x=68.75 km/hr (This is Tom's rate)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( "rate=d/t=550/11=50 km/hr
\n" ); document.write( "-----------------
\n" ); document.write( "Tom's rate is 50 km/hr.
\n" ); document.write( " \n" ); document.write( "
\n" );