document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=637358>Question 637358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hello to see if anyone can help\r<BR>\n" );
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document.write( "If I have this function f (x) = x^3/3 - x^2/2 - 2x + 2 and the tangent to the curve at the point (-1, 19/6)\r<BR>\n" );
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document.write( "What would be the equation of the tangent line?\r<BR>\n" );
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document.write( "Thanks for the help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401577 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If I have this function f (x) = x^3/3 - x^2/2 - 2x + 2 and the tangent to the curve at the point (-1, 19/6) <BR>\n" );
document.write( "What would be the equation of the tangent line? <BR>\n" );
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document.write( "Find the slope of the curve at x = -1<BR>\n" );
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document.write( "f'(x) = (1/3)*3x^2 - (1/2)2x - 2<BR>\n" );
document.write( "f'(-1) = (1)(1) - (1)(-1) -2 = 1+1-2 = 0<BR>\n" );
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document.write( "Equation of line with slope = 0, thru (-1, 19/6)<BR>\n" );
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document.write( "Answer y = 19/6<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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