document.write( "Question 637274: Find the sum of the first ten terms of the the series 1+4+16+64+256 \n" ); document.write( "
Algebra.Com's Answer #401566 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
The terms are in a geometric sequence, or geometric progression.
\n" ); document.write( "Each term is the previous one multiplied times \"4\" .
\n" ); document.write( "You may be studying geometric sequences, also called geometric progressions.
\n" ); document.write( "The symbols and names used vary a little from place to place, from book to book, and from teacher to teacher, so the symbols, and formulas may look different, but the idea is the same. I will use a popular choice for terms, symbols, and formulas. Keep in mind that your book/teacher may use slightly different ones.
\n" ); document.write( "
\n" ); document.write( "THE GENERAL THEORY (what the book may say):
\n" ); document.write( "In a geometric sequence, or geometric progression, the term number \"n\" and the number \"n-1\" (the previous one) are related by the recurrence formulas
\n" ); document.write( "\"a%5Bn%5D=a%5Bn-1%5D%2Ar\" or \"r=a%5Bn%5D%2F%28a%5Bn-1%5D%29\" ,
\n" ); document.write( "Where \"a%5Bn%5D\" is the tern number \"n\" ,
\n" ); document.write( "\"a%5Bn-1%5D\" is the previous term, and \"r\" is the common ratio.
\n" ); document.write( "The term number \"n\" can be calculated from the first term and the common ratio, using the explicit formula
\n" ); document.write( "\"a%5Bn%5D=a%5B1%5D%2Ar%5E%28n-1%29\"
\n" ); document.write( "The sum of the first \"n\" terms, \"S%5Bn%5D=a%5B1%5D%2Ba%5B2%5D\"+ ... +\"a%5Bn-1%5D+%2B+a%5Bn%5D\"
\n" ); document.write( "can be calculated as
\n" ); document.write( "\"S%5Bn%5D=a%5B1%5D%28r%5En-1%29%2F%28r-1%29\"
\n" ); document.write( "The formula can be deduced as follows:
\n" ); document.write( "\"S%5Bn%5D=a%5B1%5D%2Br%2Aa%5B1%5D%2Br%5E2%2Aa%5B1%5D\"+ ... +\"r%5E%28n-2%29%2Aa%5B1%5D%2Br%5E%28n-1%29%2Aa%5B1%5D\" , so
\n" ); document.write( "\"r%2AS%5Bn%5D=r%2Aa%5B1%5D%2Br%5E2%2Aa%5B1%5D\"+ ... +\"r%5En%2Aa%5B1%5D%2Br%5E%28n-1%29%2Aa%5B1%5D%2Br%5En%2Aa%5B1%5D\"
\n" ); document.write( "Subtracting one equation from the other, a lot of terms cancel, and you have
\n" ); document.write( "\"r%2AS%5Bn%5D-S%5Bn%5D=r%5En%2Aa%5B1%5D-a%5B1%5D\" --> \"%28r-1%29%2AS%5Bn%5D=%28r%5En-1%29%2Aa%5B1%5D\"
\n" ); document.write( "Then, dividing both sides by \"r-1\", we get
\n" ); document.write( "\"%28r-1%29%2AS%5Bn%5D=%28-1%29r%5En%2Aa%5B1%5D\" --> \"S%5Bn%5D=a%5B1%5D%28r%5En-1%29%2F%28r-1%29\"
\n" ); document.write( "Someone discovered that formula. I just remember the trick and re-discover the formula every time, because I do not need to use it often, and do not remember it.
\n" ); document.write( "
\n" ); document.write( "THE SOLUTION TO THE PROBLEM:
\n" ); document.write( "\"a%5B1%5D=1\", \"r=4\", \"n=10\"
\n" ); document.write( "Applying the formula \"S%5Bn%5D=a%5B1%5D%28r%5En-1%29%2F%28r-1%29\" , we get
\n" ); document.write( "
\n" ); document.write( "
\n" );