document.write( "Question 637250: find the value of k so that the graph of kx+3y=4 is parallel to the line through (2,-k) and(4,-1). Please help \n" ); document.write( "
Algebra.Com's Answer #401523 by reviewermath(1029)\"\" \"About 
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kx + 3y = 4 can be expressed as \"y+=+%28-k%2F3%29x+%2B+4%2F3\", therefore its slope is equal to \"-k%2F3\".\r
\n" ); document.write( "\n" ); document.write( "The slope of the line joining the points (2, -k) and (4,-1) is equal to
\n" ); document.write( "\"%28-1-%28-k%29%29%2F%284-2%29+=+%28k-1%29%2F2\".\r
\n" ); document.write( "\n" ); document.write( "Equate the two slopes because parallel line have equal slopes.\r
\n" ); document.write( "\n" ); document.write( "\"-k%2F3+=+%28k-1%29%2F2\", multiply both sides by 6
\n" ); document.write( "\"-2k+=+3k-3\"
\n" ); document.write( "\"-5k+=+-3\"
\n" ); document.write( "\"highlight%28k+=+3%2F5%29\"
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