document.write( "Question 637203: We are supposed to factor polynomials and I just don't know what I'm doing!
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Algebra.Com's Answer #401496 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-12x-63\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%5E2-4x-21%29\" Factor out the GCF \"3\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's try to factor the inner expression \"x%5E2-4x-21\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2-4x-21\", we can see that the first coefficient is \"1\", the second coefficient is \"-4\", and the last term is \"-21\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"-21\" to get \"%281%29%28-21%29=-21\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-21\" (the previous product) and add to the second coefficient \"-4\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-21\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-21\":\r
\n" ); document.write( "\n" ); document.write( "1,3,7,21\r
\n" ); document.write( "\n" ); document.write( "-1,-3,-7,-21\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-21\".\r
\n" ); document.write( "\n" ); document.write( "1*(-21) = -21
\n" ); document.write( "3*(-7) = -21
\n" ); document.write( "(-1)*(21) = -21
\n" ); document.write( "(-3)*(7) = -21\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-4\":\r
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First NumberSecond NumberSum
1-211+(-21)=-20
3-73+(-7)=-4
-121-1+21=20
-37-3+7=4
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"3\" and \"-7\" add to \"-4\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"3\" and \"-7\" both multiply to \"-21\" and add to \"-4\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-4x\" with \"3x-7x\". Remember, \"3\" and \"-7\" add to \"-4\". So this shows us that \"3x-7x=-4x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%283x-7x%29-21\" Replace the second term \"-4x\" with \"3x-7x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B3x%29%2B%28-7x-21%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B3%29%2B%28-7x-21%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B3%29-7%28x%2B3%29\" Factor out \"7\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-7%29%28x%2B3%29\" Combine like terms. Or factor out the common term \"x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "So \"3%28x%5E2-4x-21%29\" then factors further to \"3%28x-7%29%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"3x%5E2-12x-63\" completely factors to \"3%28x-7%29%28x%2B3%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"3x%5E2-12x-63=3%28x-7%29%28x%2B3%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"3%28x-7%29%28x%2B3%29\" to get \"3x%5E2-12x-63\" or by graphing the original expression and the answer (the two graphs should be identical).
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