document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=58499>Question 58499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x)=-2x^2-3x+8, find f(-2)please! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40148 by </B><A HREF=/tutors/aboutme.mpl?userid=mifarnc><B>mifarnc(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mifarnc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the f(x) is equal to -2 Then,<BR>\n" );
document.write( "replace -2 for x in the problem.<BR>\n" );
document.write( "Such as:\r<BR>\n" );
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document.write( "f(x)= -2x^2-3x+8\r<BR>\n" );
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document.write( "F(-2)= -2(-2)^2-3(-2)+8\r<BR>\n" );
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document.write( "rememebring your order of operations, complete the exponent first.\r<BR>\n" );
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document.write( "(-2)^2 = 4\r<BR>\n" );
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document.write( "-2(4)-3(-2)+8\r<BR>\n" );
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document.write( "Use order of operations again\r<BR>\n" );
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document.write( "-2x-4=-8<BR>\n" );
document.write( "-3x-2=6\r<BR>\n" );
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document.write( "so now we should have\r<BR>\n" );
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document.write( "-8+6+8\r<BR>\n" );
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document.write( "then solve \r<BR>\n" );
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document.write( "Therefore the F(-2) is 6 </SPAN>\n" );
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