document.write( "Question 637133: Calculate how much 10% salt solution and 50% salt solution must be mixed to end up with exactly 20 gallons of a 40% salt solution. \n" ); document.write( "
Algebra.Com's Answer #401457 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Calculate how much 10% salt solution and 50% salt solution must be mixed to end up with exactly 20 gallons of a 40% salt solution. \n" ); document.write( "--------- \n" ); document.write( "Equation: \n" ); document.write( "salt + salt = salt \n" ); document.write( "0.10x + 0.50(20-x) = 0.40*20 \n" ); document.write( "------ \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "10x + 50*20 - 50x = 40*20 \n" ); document.write( "-40x = -10*20 \n" ); document.write( "x = 5 gallons (amt. of 10% solution needed) \n" ); document.write( "----- \n" ); document.write( "20-x = 15 gallons (amt. of 50% solution needed) \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " |