document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=637100>Question 637100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure, in terms of x, of each side of a square if the area = x^-6x+9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401435 by </B><A HREF=/tutors/aboutme.mpl?userid=lmeeks54><B>lmeeks54(111)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lmeeks54><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lmeeks54><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your problem is missing an exponent on the x^ term; but you probably meant, x^2.  So I will go on from there.<BR>\n" );
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document.write( "The area for a square (or any rectangle) is the length of one side multiplied by an adjacent side.  For a square, the sides are of equal length.<BR>\n" );
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document.write( "The easiest way to solve this problem in terms of x is to factor the quadratic equation:<BR>\n" );
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document.write( "x^2 - 6x + 9 = (x - 3)(x - 3) = (x - 3)^2<BR>\n" );
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document.write( "The length of any of the sides of the square, in terms of x, is = x - 3<BR>\n" );
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document.write( "Email me if you have any questions. </SPAN>\n" );
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