document.write( "Question 637066: Cindy walked to work at an average speed of 6 miles an hour and biked back along the same route at 10 miles per hour. If her total traveling time was 2 hours, how long is the distance from her house to work? \n" ); document.write( "
Algebra.Com's Answer #401406 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT\r \n" ); document.write( "\n" ); document.write( "D=6T \n" ); document.write( "D=10(2-T)\r \n" ); document.write( "\n" ); document.write( "6T=10(2-T) \n" ); document.write( "6T=20-10T \n" ); document.write( "6T+10T=20 \n" ); document.write( "16T=20 \n" ); document.write( "T=20/16 \n" ); document.write( "T=1.25 HOURS FOR THE 6 MPH TRIP. \n" ); document.write( "6*1.25=10(2-1.25) \n" ); document.write( "7.5=10*.75 \n" ); document.write( "7.5=7.5 MILES FROM HOME TO WORK. \n" ); document.write( "PROOF: \n" ); document.write( "6*1.25=7.5 \n" ); document.write( "10(2-1.25)=10*.75=7.5 \n" ); document.write( " |