document.write( "Question 637015: Four years ago, Jaybee is three times the age of his daughter Juliana. In ten years, he will be twice her age. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #401360 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Four years ago, Jaybee's age\"highlight%28y%29\" is three times the age of his daughter Juliana's age\"highlight%28x%29\"
\n" ); document.write( " Question states***In ten years... he will be twice her age
\n" ); document.write( " y + 14 = 2(x + 14) | \"+y+=+3x\"
\n" ); document.write( " 3x + 14 = 2x+ 28
\n" ); document.write( " x = 14, Juliana's age 4 years ago. Father was 42 then
\n" ); document.write( "NOW: Juliana is 18. Father Jaybee is 46
\n" ); document.write( "and...10 year from now...
\n" ); document.write( " \"56+=+2%2A28\"
\n" ); document.write( " \n" ); document.write( "
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