document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636935>Question 636935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the additive inverse of -9 on the 12-hour clock. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401323 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Add 12 to -9 to get 12+(-9) = 3\r<BR>\n" );
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document.write( "So -9 and 3 are the same number on the clock (ie going backwards 9 hours is the same as going forwards 3 hours...you land on 3 each time)\r<BR>\n" );
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document.write( "So you must find a number x such that \r<BR>\n" );
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document.write( "3 + x = 0\r<BR>\n" );
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document.write( "Solve for x:\r<BR>\n" );
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document.write( "3 + x = 0\r<BR>\n" );
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document.write( "3 + x  - 3 = 0 - 3\r<BR>\n" );
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document.write( "x = -3\r<BR>\n" );
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document.write( "So -3 is the inverse of 3\r<BR>\n" );
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document.write( "Add 12 to -3 to get 12+(-3) = 9\r<BR>\n" );
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document.write( "This means that 9 is the inverse of -9\r<BR>\n" );
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document.write( "-------------------------------------------------------\r<BR>\n" );
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document.write( "Useful shortcut:\r<BR>\n" );
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document.write( "The additive inverse of 'x' is -x\r<BR>\n" );
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document.write( "Ex: x = 6 ---> additive inverse: -x = -6\r<BR>\n" );
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document.write( "Ex: x = 7 ---> additive inverse: -x = -7\r<BR>\n" );
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document.write( "etc etc </SPAN>\n" );
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