document.write( "Question 58576: I have a parabolic shape that is shown as: y = 2x^2
\n" ); document.write( "I also need to graph an ellipse: (y - 2)^2/1 + x^2/4 = 1
\n" ); document.write( "Then, I need to decide if the parabola fits in the hole.
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Algebra.Com's Answer #40132 by stanbon(75887)\"\" \"About 
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I have a parabolic shape that is shown as: y = 2x^2
\n" ); document.write( "I also need to graph an ellipse: (y - 2)^2/1 + x^2/4 = 1
\n" ); document.write( "Then, I need to decide if the parabola fits in the hole.\r
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\n" ); document.write( "You need to carefully sketch the parabolic shape and the
\n" ); document.write( "information about the ellipse on a graph. Then make a
\n" ); document.write( "determination regarding the answer to your question.
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\n" ); document.write( "Your parabolic shape has a vertex at (0,0) but you haven't
\n" ); document.write( "said what it's domain is---that would determine how far up
\n" ); document.write( "or down or to he right or to the left it goes.
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\n" ); document.write( "The ellipse has its center at (0,2).
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\n" ); document.write( "When x=0, (y-2)^2=1 ; y-2=+-1; y=3 or y=1
\n" ); document.write( "So the ellipse intersects the y-axis at (0,1) and (0,3)
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\n" ); document.write( "When y=2, x^2=4; x=+-2
\n" ); document.write( "So the ellipse passes through (2,2) and (-2,2)
\n" ); document.write( "When y=0, 4+x^2/4=1; x^2=-12;
\n" ); document.write( "So the ellipse does not touch the x-axis.
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\n" ); document.write( "Hopefully from all this you can figure out the
\n" ); document.write( "answer to your question.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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