document.write( "Question 58576: I have a parabolic shape that is shown as: y = 2x^2
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document.write( "I also need to graph an ellipse: (y - 2)^2/1 + x^2/4 = 1
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document.write( "Then, I need to decide if the parabola fits in the hole. \n" );
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Algebra.Com's Answer #40132 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I have a parabolic shape that is shown as: y = 2x^2 \n" ); document.write( "I also need to graph an ellipse: (y - 2)^2/1 + x^2/4 = 1 \n" ); document.write( "Then, I need to decide if the parabola fits in the hole.\r \n" ); document.write( "\n" ); document.write( "---------------- \n" ); document.write( "You need to carefully sketch the parabolic shape and the \n" ); document.write( "information about the ellipse on a graph. Then make a \n" ); document.write( "determination regarding the answer to your question. \n" ); document.write( "----------------- \n" ); document.write( "Your parabolic shape has a vertex at (0,0) but you haven't \n" ); document.write( "said what it's domain is---that would determine how far up \n" ); document.write( "or down or to he right or to the left it goes. \n" ); document.write( "-------- \n" ); document.write( "The ellipse has its center at (0,2). \n" ); document.write( "------------ \n" ); document.write( "When x=0, (y-2)^2=1 ; y-2=+-1; y=3 or y=1 \n" ); document.write( "So the ellipse intersects the y-axis at (0,1) and (0,3) \n" ); document.write( "--------- \n" ); document.write( "When y=2, x^2=4; x=+-2 \n" ); document.write( "So the ellipse passes through (2,2) and (-2,2) \n" ); document.write( "When y=0, 4+x^2/4=1; x^2=-12; \n" ); document.write( "So the ellipse does not touch the x-axis. \n" ); document.write( "---------- \n" ); document.write( "Hopefully from all this you can figure out the \n" ); document.write( "answer to your question. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |