document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636932>Question 636932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference of two numbers is -32. The sum of three times the smaller number and twice the larger is 134. What are the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401310 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s be the smaller the two numbers and let l be the larger of the two numbers. Then:<BR>\n" );
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document.write( "s-l=-32<BR>\n" );
document.write( "3s+2l=134<BR>\n" );
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document.write( "From the first equation we get<BR>\n" );
document.write( "s=l-32 So:<BR>\n" );
document.write( "3(l-32)+2l=134<BR>\n" );
document.write( "3l-96+2l=134<BR>\n" );
document.write( "5l=230<BR>\n" );
document.write( "l=46<BR>\n" );
document.write( "So s=l-32=46-32=14\n" );
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