document.write( "Question 636912: Find vertex and focus of parabola \r
\n" ); document.write( "\n" ); document.write( "4y = x squared - 12x + 52\r
\n" ); document.write( "\n" ); document.write( "How do you do this one?
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Algebra.Com's Answer #401283 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find vertex and focus of parabola
\n" ); document.write( "4y = x squared - 12x + 52
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\n" ); document.write( "Complete the square:
\n" ); document.write( "4y = x^2-12x+36 + 16
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\n" ); document.write( "y = (1/4)(x-6)^2 + 4
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\n" ); document.write( "Vertex: (6,4)
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\n" ); document.write( "To find the focus:
\n" ); document.write( "4p = 1/4
\n" ); document.write( "p = 1/16
\n" ); document.write( "----
\n" ); document.write( "Focus is 1/16 above the vertex:
\n" ); document.write( "Focus: (6 , 4+(1/16)) or (6,67/16)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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