document.write( "Question 636912: Find vertex and focus of parabola \r
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document.write( "4y = x squared - 12x + 52\r
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document.write( "How do you do this one? \n" );
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Algebra.Com's Answer #401283 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find vertex and focus of parabola \n" ); document.write( "4y = x squared - 12x + 52 \n" ); document.write( "---- \n" ); document.write( "Complete the square: \n" ); document.write( "4y = x^2-12x+36 + 16 \n" ); document.write( "--- \n" ); document.write( "y = (1/4)(x-6)^2 + 4 \n" ); document.write( "--- \n" ); document.write( "Vertex: (6,4) \n" ); document.write( "---- \n" ); document.write( "To find the focus: \n" ); document.write( "4p = 1/4 \n" ); document.write( "p = 1/16 \n" ); document.write( "---- \n" ); document.write( "Focus is 1/16 above the vertex: \n" ); document.write( "Focus: (6 , 4+(1/16)) or (6,67/16) \n" ); document.write( "========================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |