document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=636780>Question 636780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two years hence, John's mother will be twice his age.Five years hence his father will be thrice his present age.What is the difference between the ages of his parents,if the sum of all the three ages is 105? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #401243 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=401243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let<BR>\n" );
document.write( "Present age of mother = m years old<BR>\n" );
document.write( "Present age of father = f years old<BR>\n" );
document.write( "Present age of John = j years old\r<BR>\n" );
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document.write( "Two years hence<BR>\n" );
document.write( "mother will be = m+2 years old<BR>\n" );
document.write( "John will be = j+2 years old<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "mother will be twice his age<BR>\n" );
document.write( "m+2=2(j+2)<BR>\n" );
document.write( "m+2=2j+4<BR>\n" );
document.write( "m=2j+4-2<BR>\n" );
document.write( "m=2j+2.................(1)\r<BR>\n" );
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document.write( "Five years hence<BR>\n" );
document.write( "father will be = f+5 years old<BR>\n" );
document.write( "John will be = j+5 years old<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "father will be thrice his present age<BR>\n" );
document.write( "f+5=3(j+5)<BR>\n" );
document.write( "f+5=3j+15<BR>\n" );
document.write( "f=3j+15-5<BR>\n" );
document.write( "f=3j+10..................(2)\r<BR>\n" );
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document.write( "the sum of all the three ages is 105<BR>\n" );
document.write( "m+j+f=105<BR>\n" );
document.write( "Put the value of m and f from (1) and (2) to above equation<BR>\n" );
document.write( "2j+2+j+3j+10=105<BR>\n" );
document.write( "6j+12=105<BR>\n" );
document.write( "6j=105-12<BR>\n" );
document.write( "6j=93<BR>\n" );
document.write( "6j/6=93/6<BR>\n" );
document.write( "j=31/2<BR>\n" );
document.write( "Put the value of j in (1)<BR>\n" );
document.write( "m=2j+2.................(1)<BR>\n" );
document.write( "m=2(31/2)+2<BR>\n" );
document.write( "m=31+2<BR>\n" );
document.write( "m=33\r<BR>\n" );
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document.write( "Put the value of j in (2)<BR>\n" );
document.write( "f=3j+10..................(2)<BR>\n" );
document.write( "f=3(31/2)+10<BR>\n" );
document.write( "f=93/2+10<BR>\n" );
document.write( "f=(93+20)/2<BR>\n" );
document.write( "f=113/2<BR>\n" );
document.write( "f=56.5\r<BR>\n" );
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document.write( "Difference b/w parents ages = f-m=56.5-33= 23.5 years. </SPAN>\n" );
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