document.write( "Question 636594: / = a fraction
\n" ); document.write( "1/5x + 1/3y = -8/15
\n" ); document.write( "1/5x + 4y = 34/5
\n" ); document.write( "solve the system by the substitution method. \n" ); document.write( "

Algebra.Com's Answer #401215 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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$\"1%2F5\"$ x + $\"1%2F3\"$ y = $\"-8%2F15\"$
\n" ); document.write( " $\"1%2F5\"$ x + 4y = $\"34%2F5\"$
\n" ); document.write( "Get rid of the fractions, multiply the first equation by 15, the 2nd eq by 5
\n" ); document.write( "3x + 5y = -8
\n" ); document.write( "x + 20y = 34
\n" ); document.write( "Use the 2nd equation for substitution in the 1st equation
\n" ); document.write( "x = -20y + 34
\n" ); document.write( ":
\n" ); document.write( "3(-20y+34) + 5y = -8
\n" ); document.write( "-60y + 102 + 5y = -8
\n" ); document.write( "-55y = -8 -102
\n" ); document.write( "-55y = -110
\n" ); document.write( "y = $\"%28-110%29%2F%28-55%29\"$
\n" ); document.write( "y = +2
\n" ); document.write( ":
\n" ); document.write( "Replace y with 2 in x = -20y + 34
\n" ); document.write( "x = -20(2) + 34
\n" ); document.write( "x = -40 + 34
\n" ); document.write( "x = -6
\n" ); document.write( ":
\n" ); document.write( "Solution x=-6, y=2
\n" ); document.write( "Check this in the equation: 3x + 5y = -8
\n" ); document.write( "3(-6) + 5(2) = -8
\n" ); document.write( "-18 + 10 = -8; confirms our solution \n" ); document.write( "

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