document.write( "Question 636756: x^2+(x+2)^2=(x+4)^2
\n" ); document.write( "x^2+x^2+4x+4=x^2+8x+16
\n" ); document.write( "x^2-4x-12=0
\n" ); document.write( "x^2-6x+2x-12=0
\n" ); document.write( "x(x-6)+2(x-6)=0
\n" ); document.write( "(x-6)(x=2)=o
\n" ); document.write( "x=6 I solved this problem and I have tried so hard to check, but I just dont know how to check this please help me \n" ); document.write( "

Algebra.Com's Answer #401208 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "x^2-4x-12=0  Good Work!
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document.write( "(x-6)(x + 2)= 0   
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document.write( " x = 6  0r x = -2
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document.write( "To check: Use EQ given to You and substitute values found
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document.write( "x^2+(x+2)^2=(x+4)^2
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document.write( "   x = 6 checks
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document.write( "      x = -2 checks \n" );
document.write( "

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