document.write( "Question 636714: Please help me solve this problem: Maria is 18 years old. She is twice as old as Anna was when she was as old as Anna now. How old is Anna now? \n" ); document.write( "
Algebra.Com's Answer #401206 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Maria is 18 years old now \n" ); document.write( "Let x=Anna's age now \n" ); document.write( "Let y=number of years that have passed since Maria was x years old \n" ); document.write( "Sooo \n" ); document.write( "18-y=x \n" ); document.write( "x+y=18---eq1 \n" ); document.write( "Then when Maria was x years old , Anna was x-y years old \n" ); document.write( "Sooo \n" ); document.write( "18=2(x-y)=2x-2y or \n" ); document.write( "x-y=9----eq2\r \n" ); document.write( "\n" ); document.write( "Add eq1 and eq2 and we get: \n" ); document.write( "2x=27 \n" ); document.write( "x=13.5 Anna's age now \n" ); document.write( "substitute 13.5 into eq1 \n" ); document.write( "y=18-13.5=4.5 number of years that have passed since Maria was 13.5 years old. So, when Maria was 13.5, Anna was 13.5-4.5=9 \n" ); document.write( "18=2*9\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " \n" ); document.write( " |