document.write( "Question 636714: Please help me solve this problem: Maria is 18 years old. She is twice as old as Anna was when she was as old as Anna now. How old is Anna now? \n" ); document.write( "
Algebra.Com's Answer #401206 by ptaylor(2198)\"\" \"About 
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Maria is 18 years old now
\n" ); document.write( "Let x=Anna's age now
\n" ); document.write( "Let y=number of years that have passed since Maria was x years old
\n" ); document.write( "Sooo
\n" ); document.write( "18-y=x
\n" ); document.write( "x+y=18---eq1
\n" ); document.write( "Then when Maria was x years old , Anna was x-y years old
\n" ); document.write( "Sooo
\n" ); document.write( "18=2(x-y)=2x-2y or
\n" ); document.write( "x-y=9----eq2\r
\n" ); document.write( "\n" ); document.write( "Add eq1 and eq2 and we get:
\n" ); document.write( "2x=27
\n" ); document.write( "x=13.5 Anna's age now
\n" ); document.write( "substitute 13.5 into eq1
\n" ); document.write( "y=18-13.5=4.5 number of years that have passed since Maria was 13.5 years old. So, when Maria was 13.5, Anna was 13.5-4.5=9
\n" ); document.write( "18=2*9\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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