document.write( "Question 636752: 3. The Perimeter of a rectangle is 26. If 5in is added to the width of the rectangle ,
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Algebra.Com's Answer #401205 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "If 5in is added to the width of the rectangle , a square with perimeter 36in is Obtained.
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document.write( " Square has sides = 9in , width of rectangle:  w+5= 9, w = 4in
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document.write( "Question states*** Original Rectangle had a P = 26in
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document.write( "   L + w = 13in
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document.write( "   L + 4 = 13in
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document.write( "       L = 9in\r
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document.write( " Dimensions of the Original rectangle were 4in by 9in
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