document.write( "Question 636751: 2. Josephine and Hilda are sisters. hilda is 17yrs. older than Josephine, In 3yrs.
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document.write( "Hildas age will be twice Josephine's age.
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document.write( "Q: what are their age in 3yrs. from Now? \n" );
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Algebra.Com's Answer #401201 by ptaylor(2198) You can put this solution on YOUR website! Let x=Josephine's age in three years \n" ); document.write( "Then x+17=Hilda's age in three years \n" ); document.write( "Sooo \n" ); document.write( "x+17=2x subtract x from each side \n" ); document.write( "x=17----Josephine's age in three years \n" ); document.write( "x+17=17+17=34---Hilda's age in three years\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " \n" ); document.write( " |